Basic idea - copy the boot record of our linux distro partition to Windows , and using BCDEdit to create a new entry in the BCD store that will point to that file. This way Windows will display a menu at boot time that will give you a choice between Windows and Linux distro.
Boot into Linux
First, create a directory to save boot record. Open a terminal and enter the following:
sudo su
mkdir /mnt/share
Write the first 512 bytes of our linux disro partition(sdxy) to a file
dd if=/dev/sdx of=/mnt/share/linux.bin bs=512 count=1
copy the linux.bin file located in /mnt/share/ to any other desired location.(will need it after booting into windows)
Boot into windows
open the volume where you copied the linux.bin file.
Copy that file to the root of the Windows volume (e.g., C:).
use BCDEdit to add an entry to Windows BCD store. Administrative privileges are required to use BCDEdit, so use Win+r, type cmd, and then press CTRL+SHIFT+ENTER. start by creating an entry for our Linux distribution. Note here that you are free to choose another entry name if desired:
bcdedit /create /d “Linux” /application bootsector
BCDEdit will return an alphanumeric identifier for this entry that I will refer to as {ID} in the remaining steps. You’ll need to replace {ID} by the actual returned identifier.Next, specify which partition hosts a copy of the linux.bin file:
bcdedit /set {ID} device partition=c:
The path to our linux.bin file:
bcdedit /set {ID} path \linux.bin
An entry to the displayed menu at boot time:
bcdedit /displayorder {ID} /addlast
and finally, let’s specify how long the menu choices will be displayed:
bcdedit /timeout 30
On a final note, if at any time you want to eliminate the Linux menu option simply delete the BCD store entry you created using the following command:
bcdedit /delete {ID}
Now
Make windows bootloader the default
bootsect /nt60 C: /force /mbr
That’s it! Now reboot and you will be presented with menu where you can choose to boot to Windows or Linux.
